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Dissociation PES curves with Qunova HiVQE

Note

Quantum Functions are a beta feature available only to IBM Quantum® Premium Plan, Flex Plan, and On-Prem (through the IBM Quantum Platform API) Plan users. Beta features are subject to change.

Usage estimate (NOTE: This is an estimate only. Your runtime might vary.)

  • Li2S: Five minutes QPU time on a Heron r2 processor
  • FeP-NO: Five minutes QPU time on a Heron r2 processor

Background

Accurately calculating chemical reaction energies is crucial for scientific advancements in materials science, chemical engineering, drug discovery, and other fields. Among various chemical systems, the Li-S system has garnered significant interest for understanding and developing new battery compositions. This tutorial provides hands-on experience in calculating the Li-S bond dissociation potential energy surface (PES) of a Li2SLi_2S system by removing one lithium atom using HI-VQE calculations. The results can be compared with reference calculations (CASCI) as well as classical methods like Hartree-Fock (HF) for a 20-qubit problem.

The lithium–sulfur example connects this workflow to research on next-generation batteries for energy storage. Calculating how energy changes as a Li–S bond breaks provides molecular-level insight relevant to understanding the chemical transformations in these systems. More broadly, potential energy surfaces are tools for studying reaction pathways and catalysts for more resource-efficient chemical processes.


Requirements

Install the following dependencies to run the code in this tutorial.

!pip install --upgrade pip
!pip install -U qiskit-ibm-catalog pyscf numpy matplotlib typing_extensions h5py

Setup

To run this tutorial, load the qunova/hivqe-chemistry function through FunctionsCatalog, as in Get started with Qiskit Functions. You need an IBM Quantum Premium Plan, Flex Plan, or On-Prem (IBM Quantum Platform API) Plan account.

from qiskit_ibm_catalog import FunctionsCatalog
from pyscf import mcscf  # gto and scf come with the size calculator below
import matplotlib.pyplot as plt
import pprint

catalog = FunctionsCatalog(
    channel="ibm_quantum_platform",
    instance="INSTANCE_CRN",
    # For `token`, use the 44-character API_KEY you created
    # and saved from the IBM Quantum Platform Home dashboard
    token="YOUR_API_KEY",
)

hivqe = catalog.load("qunova/hivqe-chemistry")

# Use the least busy QPU available to you
backend_name = catalog.least_busy(operational=True).name

Before you run

Every run below passes a function_size, which sets the compute profile it runs on. The size each run needs is worked out with the size calculator from the guide, which you load in the next cell: M for Part 1, and L for Part 2, which runs with a larger max_states. See Function sizes in the guide.

With a license, run everything below unchanged; no license token is needed.

With trial access, runs are limited to function size S, so the runs in this tutorial are rejected with error code 4500.

The size calculator needs only PySCF, which you installed above. It reads your inputs and submits nothing. Open the code below and run it.

  • # Size calculator for Qunova HI-VQE Chemistry. Requires PySCF only.
    #
    # calculate_function_size(geometry, max_states=..., molecule_options=...) returns "S", "M"
    # or "L" from two things: the number of qubits the problem needs, and the
    # max_states it is run with. A problem is the smallest size whose bounds it fits
    # on both; above any bound of "M" it is "L".
    #
    # The qubits are two per active orbital. The active space is the orbitals AVAS
    # selects if avas_aolabels is set, else active_orbitals if set, else every
    # orbital in the basis. With fcidump_file_name, the path of an FCIDUMP file, it
    # is every orbital of the file, and geometry and molecule_options are ignored,
    # as the function ignores them. max_states is the function's argument of that
    # name. Other inputs are accepted and ignored.
    import gzip
    import re
    from typing import Any, Literal
    
    from pyscf import gto, scf
    from pyscf.mcscf import avas
    
    
    Size = Literal["S", "M", "L"]
    _ORDER = {"S": 0, "M": 1, "L": 2}
    
    # Upper bounds (inclusive) for each size, on the number of qubits and on
    # max_states. A problem above either bound of a size does not fit it; above
    # every bound here it is "L".
    _BOUNDS = (
        ("S", 20, 10**3),
        ("M", 48, 10**7),
    )
    
    # The function's defaults for the molecule_options that decide the active space.
    _DEFAULTS = {
        "active_orbitals": None,
        "avas_aolabels": None,
        "avas_threshold": 0.2,
        "basis": "sto-3g",
        "charge": 0,
        "symmetry": False,
        "symmetry_subgroup": None,
        "unit": "angstrom",
        "nucmod": None,
        "pseudo": None,
        "cart": False,
        "magmom": None,
    }
    
    # AVAS weights below this are numerical noise; counting them would make the size vary
    # from one call to the next.
    _AVAS_WEIGHT_TOLERANCE = 1e-10
    
    
    def calculate_function_size(problem: Any, **kwargs: Any) -> Size:
        """Return the size ("S", "M" or "L") required to run the function."""
        metrics = _measure(problem, **kwargs)
        metrics["max_states"] = _max_states(kwargs)
        return size_for(metrics)
    
    
    def size_for(metrics: dict) -> Size:
        """The smallest size whose qubit and max_states bounds both fit the metrics."""
        for size, max_qubits, max_states in _BOUNDS:
            if (
                metrics["num_qubits"] <= max_qubits
                and metrics["max_states"] <= max_states
            ):
                return size
        return "L"
    
    
    def _max_states(kwargs: dict) -> int:
        """max_states as the function takes it: a positive integer, which it requires."""
        value = kwargs.get("max_states")
        # JSON Schema counts 1000.0 as an integer, so the function can receive one.
        if isinstance(value, float) and value.is_integer():
            value = int(value)
        if isinstance(value, bool) or not isinstance(value, int) or value < 1:
            raise ValueError("max_states must be given as a positive integer.")
        return value
    
    
    def _measure(problem: Any, **kwargs: Any) -> dict:
        """Return the number of qubits the run uses for this geometry and these options."""
        if kwargs.get("fcidump_file_name"):
            return {
                "num_qubits": 2
                * _fcidump_num_orbitals(kwargs["fcidump_file_name"])
            }
        options = {**_DEFAULTS, **(kwargs.get("molecule_options") or {})}
        mol = gto.M(
            atom=problem,
            basis=options["basis"],
            spin=0,  # the function runs singlets only
            charge=options["charge"],
            symmetry=options["symmetry"],
            symmetry_subgroup=options["symmetry_subgroup"],
            unit=options["unit"],
            nucmod=options["nucmod"],
            pseudo=options["pseudo"],
            cart=options["cart"],
            magmom=options["magmom"],
            verbose=0,
        )
    
        if options["avas_aolabels"] is None:
            # The active space is the orbitals given, or the whole basis; building the molecule
            # is enough to know it.
            if options["active_orbitals"]:
                return {"num_qubits": 2 * len(options["active_orbitals"])}
            return {"num_qubits": 2 * mol.nao_nr()}
    
        # AVAS picks the active space from an RHF, so it has to run one.
        rhf = scf.RHF(mol)
        rhf.verbose = 0
        rhf.kernel()
        selection = avas.AVAS(
            mf=rhf,
            aolabels=options["avas_aolabels"],
            threshold=max(options["avas_threshold"], _AVAS_WEIGHT_TOLERANCE),
        )
        selection.verbose = 0
        selection.kernel()
        return {"num_qubits": 2 * selection.ncas}
    
    
    # An FCIDUMP header is read up to its end (&END or /). It is a few lines; its
    # only part that grows with the problem is ORBSYM, a few characters per orbital.
    _FCIDUMP_MAX_HEADER_LINES = 1000
    
    
    def _fcidump_num_orbitals(path: str) -> int:
        """NORB from the header of an FCIDUMP file, plain or gzip-compressed,
        without reading the integrals."""
        with open(path, "rb") as raw:
            gzipped = raw.read(2) == b"\x1f\x8b"
        opener = gzip.open if gzipped else open
        header = []
        try:
            with opener(path, "rt") as in_file:
                for line_number, line in enumerate(in_file):
                    header.append(line.upper())
                    if "&END" in header[-1] or "/" in line:
                        break
                    if line_number >= _FCIDUMP_MAX_HEADER_LINES:
                        raise ValueError(
                            "No end of header (&END or /) was found in the FCIDUMP file."
                        )
                else:
                    raise ValueError(
                        "No end of header (&END or /) was found in the FCIDUMP file."
                    )
        except (UnicodeDecodeError, OSError, EOFError) as error:
            raise ValueError(
                "The FCIDUMP file could not be read as text or as gzip-compressed text."
            ) from error
        match = re.search(r"NORB\s*=\s*(\d+)", "".join(header))
        if match is None or int(match.group(1)) < 1:
            raise ValueError(
                "No valid NORB entry was found in the FCIDUMP file header."
            )
        return int(match.group(1))

Part 1: Li2S (20Q)

Step 1: Map classical inputs to a quantum problem

Define Li2SLi_2S geometries in dictionary format for different bond distance of Li-S to calculate PES curve. These geometries are optimized using B3LYP/631g calculations.

str_geometries = {
    "1.51": "S -1.239044 0.671232 -0.030374; Li -1.506327 0.432403 -1.498949; Li -0.899996 0.973348 1.826768",
    "1.91": "S -1.215858 0.692272 0.099232; Li -1.553305 0.390283 -1.758043; Li -0.876205 0.994426 1.956257",
    "2.40": "S -1.741432 0.680397 0.346702; Li -0.529307 0.488006 -1.729343; Li -1.284307 0.989409 2.177209",
    "3.10": "S -2.347450 0.657089 0.566194; Li -0.199353 0.527517 -1.665148; Li -1.008243 0.973206 1.893522",
    "3.80": "S -2.707255 0.674298 0.909161; Li 0.079218 0.552012 -1.671656; Li -0.927010 0.931502 1.557063",
    "4.50": "S -2.913363 0.709175 1.276987; Li 0.368656 0.559989 -1.798088; Li -1.010340 0.888647 1.315670",
}
str_geometries

Output:

{'1.51': 'S -1.239044 0.671232 -0.030374; Li -1.506327 0.432403 -1.498949; Li -0.899996 0.973348 1.826768',
 '1.91': 'S -1.215858 0.692272 0.099232; Li -1.553305 0.390283 -1.758043; Li -0.876205 0.994426 1.956257',
 '2.40': 'S -1.741432 0.680397 0.346702; Li -0.529307 0.488006 -1.729343; Li -1.284307 0.989409 2.177209',
 '3.10': 'S -2.347450 0.657089 0.566194; Li -0.199353 0.527517 -1.665148; Li -1.008243 0.973206 1.893522',
 '3.80': 'S -2.707255 0.674298 0.909161; Li 0.079218 0.552012 -1.671656; Li -0.927010 0.931502 1.557063',
 '4.50': 'S -2.913363 0.709175 1.276987; Li 0.368656 0.559989 -1.798088; Li -1.010340 0.888647 1.315670'}

HI-VQE calculations will be performed with the options defined below. Using sto3g basis for Li2SLi_2S, there are 19 spatial orbitals with 22 electrons. To run (10o,12e) case with HI-VQE calculation, you can define 10 active orbitals and freeze the five lowest orbitals, which leaves 12 active electrons. At each iteration, 100 shots will be used to sample electron configuration generated by the ExcitationPreserving quantum circuit (epa) with circular entanglement and two repetitions (reps). The maximum number of iteration is set to be 30 to ensure termination of iteration with energy convergence.

molecule_options = {
    "basis": "sto3g",
    "active_orbitals": list(range(5, 15)),
    "frozen_orbitals": list(range(5)),
}

hivqe_options = {
    "shots": 100,
    "max_iter": 30,
    "ansatz": "epa",
    "ansatz_entanglement": "circular",
    "ansatz_reps": 2,
}

Step 2 and 3: Optimize problem for quantum hardware execution and execute using the HI-VQE Chemistry function

Set up the for loop to run HI-VQE calculations with geometries with options defined below. Jobs are submitted in the for loop. In this tutorial, you will submit six geometries and retrieve results when they are all completed. In the main function run, you need to define the max_states and max_expansion_states to control the maximum size of the subspace matrix and to control how many states can be generated using classical CI expansion methods per iteration. The function job ids will be stored in the dictionary with each geometry label to further track and process the output.

These geometries need 20 qubits and run with max_states=40000, so the calculator gives M. They share their active space and max_states, so the size is calculated once.

size_li2s = calculate_function_size(
    str_geometries["1.51"],
    max_states=40000,
    molecule_options=molecule_options,
)
print(size_li2s)  # "M"
info_jobid = {}
for dis, geom in str_geometries.items():
    hivqe_run = hivqe.run(
        geometry=geom,
        backend_name=backend_name,
        function_size=size_li2s,
        max_states=40000,
        max_expansion_states=100,
        molecule_options=molecule_options,
        hivqe_options=hivqe_options,
    )
    status = hivqe_run.status()
    info_jobid[dis] = hivqe_run.job_id
print(info_jobid)

Output:

{'1.51': 'de3b8818-c9db-4fa3-a3c2-d51551c2dfaf', '1.91': '55d9467a-fc85-49a8-9bc6-8f6990e421e5', '2.40': '415112b3-69ff-4d53-8b10-cb4e3be68c9e', '3.10': 'ef67b600-3887-4225-b872-e354dfdf8454', '3.80': 'b16d3502-a9e4-4560-9775-852e9d07e70f', '4.50': '0c0bffc7-af77-4a56-a656-2a2610c991d6'}

Let's check whether all jobs are still running or completed.

completed_jobs_num = 0
running_jobs_num = 0
completed_jobs = {}
for i, info in enumerate(info_jobid.items()):
    dis, job_id = info
    submitted_job = catalog.get_job_by_id(job_id)
    stat = submitted_job.status()
    print(dis, submitted_job.job_id, stat)
    if stat == "DONE":
        completed_jobs_num += 1
        completed_jobs[dis] = submitted_job
    if (stat == "RUNNING") or (stat == "QUEUED"):
        running_jobs_num += 1

print(
    f"Completed {completed_jobs_num} job, "
    f"Running or Queued {running_jobs_num} job"
)

Output:

1.51 de3b8818-c9db-4fa3-a3c2-d51551c2dfaf DONE
1.91 55d9467a-fc85-49a8-9bc6-8f6990e421e5 DONE
2.40 415112b3-69ff-4d53-8b10-cb4e3be68c9e DONE
3.10 ef67b600-3887-4225-b872-e354dfdf8454 DONE
3.80 b16d3502-a9e4-4560-9775-852e9d07e70f DONE
4.50 0c0bffc7-af77-4a56-a656-2a2610c991d6 DONE
Completed 6 job, Running or Queued 0 job

Once all jobs are completed, let's retrieve all calculation results.

hivqe_result = {}
if len(info_jobid) == completed_jobs_num:
    print("All jobs are completed")
    for i, job in enumerate(completed_jobs.items()):
        dis, cal = job
        print(dis, cal.result()["energy"])
        hivqe_result[str(dis)] = cal.result()["energy"]

Output:

All jobs are completed
1.51 -407.8944801731773
1.91 -407.9800570932916
2.40 -407.9372992999806
3.10 -407.86278336000134
3.80 -407.83092972296157
4.50 -407.82971011225766
pprint.pprint(hivqe_result)

Output:

{'1.51': -407.8944801731773,
 '1.91': -407.9800570932916,
 '2.40': -407.9372992999806,
 '3.10': -407.86278336000134,
 '3.80': -407.83092972296157,
 '4.50': -407.82971011225766}

The results file for each of the calculations can be downloaded into the current directory, under its own name, with catalog.file_download(). See Manage files across runs for how files are moved to and from a function. These files contain "states", "eigenvector", "energy_history", "final_energy", and "final_energy_variance".

if len(info_jobid) == completed_jobs_num:
    print("All jobs are completed")
    for i, job in enumerate(completed_jobs.items()):
        dis, cal = job
        print(dis, cal.result()["results_file_name"])
        results_file_name = cal.result()["results_file_name"]
        catalog.file_download(
            results_file_name, hivqe, target_name=results_file_name
        )

The results can be read from the h5 file as follows:

import h5py

# The results file of the 1.51 calculation
results_file_name = completed_jobs["1.51"].result()["results_file_name"]

# Read data from the results file for a single calculation
with h5py.File(results_file_name, "r") as f:
    states = f["states"].asstr()[:]
    eigenvector = f["eigenvector"][:]
    energy_history = f["energy_history"][:]
    final_energy = f["final_energy"][0]
    final_energy_variance = f["final_energy_variance"][0]

The entire QPU runtime used in the job can be tracked by logging in to IBM Quantum Platform and viewing submitted jobs with the qunova-chemistry-hivqe tag. To find the Qiskit Runtime jobs of one function job from code, see Access the associated Quantum Compute jobs.

Step 4: Post-process and compare with classical methods

Classical reference calculation (CASCI) can be conducted for (10o,12e) to validate HI-VQE results.

ref_geometries = {
    "1.31": "S -1.250686 0.660708 -0.095168; Li -1.482812 0.453464 -1.369406; Li -0.911870 0.962810 1.762020",
    "1.41": "S -1.244856 0.665971 -0.062773; Li -1.494574 0.442933 -1.434177; Li -0.905937 0.968078 1.794395",
    "1.51": "S -1.239044 0.671232 -0.030374; Li -1.506327 0.432403 -1.498949; Li -0.899996 0.973348 1.826768",
    "1.61": "S -1.233245 0.676492 0.002027; Li -1.518073 0.421873 -1.563722; Li -0.894049 0.978617 1.859141",
    "1.71": "S -1.227453 0.681752 0.034429; Li -1.529816 0.411343 -1.628496; Li -0.888099 0.983887 1.891513",
    "1.81": "S -1.221659 0.687012 0.066831; Li -1.541558 0.400813 -1.693270; Li -0.882150 0.989157 1.923885",
    "1.91": "S -1.215858 0.692272 0.099232; Li -1.553305 0.390283 -1.758043; Li -0.876205 0.994426 1.956257",
    "2.01": "S -1.209887 0.697544 0.131599; Li -1.565136 0.379748 -1.822800; Li -0.870344 0.999691 1.988646",
    "2.11": "S -1.203945 0.702813 0.163973; Li -1.576953 0.369214 -1.887560; Li -0.864469 1.004956 2.021033",
    "2.21": "S -1.198023 0.708081 0.196350; Li -1.588760 0.358680 -1.952322; Li -0.858584 1.010221 2.053417",
    "2.30": "S -1.365426 0.717714 0.367060; Li -0.689401 0.458925 -1.828368; Li -1.500219 0.981173 2.255876",
    "2.31": "S -1.192118 0.713348 0.228731; Li -1.600559 0.348146 -2.017085; Li -0.852690 1.015488 2.085800",
    "2.40": "S -1.741432 0.680397 0.346702; Li -0.529307 0.488006 -1.729343; Li -1.284307 0.989409 2.177209",
    "2.50": "S -1.885961 0.669986 0.365815; Li -0.461563 0.499084 -1.695846; Li -1.207523 0.988741 2.124599",
    "2.60": "S -1.977163 0.665155 0.389784; Li -0.416654 0.504966 -1.683655; Li -1.161229 0.987690 2.088439",
    "2.70": "S -2.063642 0.661518 0.418977; Li -0.367600 0.510505 -1.676408; Li -1.123804 0.985788 2.051998",
    "2.80": "S -2.141072 0.659218 0.451663; Li -0.323153 0.515056 -1.673046; Li -1.090821 0.983538 2.015951",
    "2.90": "S -2.212097 0.657968 0.487535; Li -0.281989 0.518909 -1.672407; Li -1.060960 0.980935 1.979440",
    "3.00": "S -2.281477 0.657123 0.525155; Li -0.239607 0.523326 -1.668669; Li -1.033963 0.977363 1.938081",
    "3.10": "S -2.347450 0.657089 0.566194; Li -0.199353 0.527517 -1.665148; Li -1.008243 0.973206 1.893522",
    "3.20": "S -2.410882 0.657532 0.608912; Li -0.157788 0.532069 -1.659971; Li -0.986376 0.968211 1.845627",
    "3.30": "S -2.470306 0.658818 0.654893; Li -0.118007 0.536237 -1.656311; Li -0.966733 0.962757 1.795986",
    "3.40": "S -2.525776 0.660762 0.702910; Li -0.078312 0.540189 -1.654076; Li -0.950958 0.956861 1.745734",
    "3.50": "S -2.576885 0.663376 0.752788; Li -0.039076 0.543706 -1.654536; Li -0.939085 0.950730 1.696316",
    "3.60": "S -2.623930 0.666534 0.803853; Li 0.000274 0.546839 -1.657697; Li -0.931390 0.944439 1.648412",
    "3.70": "S -2.667364 0.670217 0.856250; Li 0.039572 0.549616 -1.663265; Li -0.927254 0.937980 1.601583",
    "3.80": "S -2.707255 0.674298 0.909161; Li 0.079218 0.552012 -1.671656; Li -0.927010 0.931502 1.557063",
    "3.90": "S -2.744005 0.678718 0.962425; Li 0.119268 0.554073 -1.682595; Li -0.930310 0.925021 1.514738",
    "4.00": "S -2.777891 0.683415 1.015798; Li 0.159751 0.555810 -1.696024; Li -0.936907 0.918587 1.474794",
    "4.10": "S -2.809179 0.688333 1.069057; Li 0.200678 0.557234 -1.711873; Li -0.946546 0.912245 1.437385",
    "4.20": "S -2.838194 0.693443 1.122205; Li 0.242066 0.558401 -1.729770; Li -0.958918 0.905968 1.402134",
    "4.30": "S -2.864984 0.698619 1.174415; Li 0.283858 0.559186 -1.750539; Li -0.973920 0.900007 1.370693",
    "4.40": "S -2.889984 0.703887 1.226140; Li 0.326068 0.559728 -1.773231; Li -0.991131 0.894196 1.341660",
    "4.50": "S -2.913363 0.709175 1.276987; Li 0.368656 0.559989 -1.798088; Li -1.010340 0.888647 1.315670",
}
rhf_result = {}
casci_result = {}

cas_list = molecule_options["active_orbitals"]
distance_ref = []
for dis, geom in ref_geometries.items():
    distance_ref.append(dis)
    mole = gto.M(atom=geom, basis=molecule_options["basis"])
    mole.verbose = 0
    # RHF energy
    mf = scf.RHF(mole).run()
    mo_occ = mf.mo_occ
    num_elecs_as = int(sum([mo_occ[idx] for idx in cas_list]))

    rhf_result[str(dis)] = mf.e_tot
    # CASCI energy
    casci_solver = mcscf.CASCI(mf, len(cas_list), num_elecs_as)
    orbs = mcscf.addons.sort_mo(casci_solver, mf.mo_coeff, cas_list, base=0)
    casci_solver.kernel(orbs)
    casci_result[str(dis)] = casci_solver.e_tot
    print(
        f"d={dis:4.3} RHF Energy: {mf.e_tot:14.10}, "
        f"CASCI Energy: {casci_solver.e_tot:14.10}"
    )

Output:

d=1.3  RHF Energy:   -407.7137006, CASCI Energy:   -407.7193917
d=1.4  RHF Energy:   -407.8183196, CASCI Energy:   -407.8245211
d=1.5  RHF Energy:   -407.8878013, CASCI Energy:   -407.8944802
d=1.6  RHF Energy:   -407.9315356, CASCI Energy:   -407.9385663
d=1.7  RHF Energy:   -407.9569034, CASCI Energy:   -407.9641258
d=1.8  RHF Energy:   -407.9693681, CASCI Energy:   -407.9766313
d=1.9  RHF Energy:   -407.9728592, CASCI Energy:   -407.9800572
d=2.0  RHF Energy:   -407.9701684, CASCI Energy:   -407.9772549
d=2.1  RHF Energy:   -407.9632701, CASCI Energy:   -407.9702381
d=2.2  RHF Energy:   -407.9535584, CASCI Energy:   -407.9604007
d=2.3  RHF Energy:   -407.9420173, CASCI Energy:   -407.9487043
d=2.3  RHF Energy:   -407.9420156, CASCI Energy:   -407.9487024
d=2.4  RHF Energy:   -407.9297216, CASCI Energy:   -407.9372993
d=2.5  RHF Energy:      -407.9172, CASCI Energy:   -407.9261859
d=2.6  RHF Energy:   -407.9061139, CASCI Energy:    -407.915961
d=2.7  RHF Energy:   -407.8937118, CASCI Energy:    -407.904259
d=2.8  RHF Energy:   -407.8816389, CASCI Energy:   -407.8928292
d=2.9  RHF Energy:   -407.8700448, CASCI Energy:   -407.8819574
d=3.0  RHF Energy:    -407.859054, CASCI Energy:   -407.8719092
d=3.1  RHF Energy:   -407.8487619, CASCI Energy:   -407.8628304
d=3.2  RHF Energy:   -407.8392304, CASCI Energy:   -407.8548482
d=3.3  RHF Energy:   -407.8304842, CASCI Energy:   -407.8480217
d=3.4  RHF Energy:   -407.8225124, CASCI Energy:   -407.8423743
d=3.5  RHF Energy:   -407.8152758, CASCI Energy:   -407.8378892
d=3.6  RHF Energy:   -407.8087161, CASCI Energy:   -407.8345331
d=3.7  RHF Energy:    -407.802764, CASCI Energy:   -407.8322563
d=3.8  RHF Energy:   -407.7973458, CASCI Energy:     -407.83093
d=3.9  RHF Energy:   -407.7923883, CASCI Energy:   -407.8303555
d=4.0  RHF Energy:   -407.7878216, CASCI Energy:     -407.83025
d=4.1  RHF Energy:    -407.783582, CASCI Energy:   -407.8303243
d=4.2  RHF Energy:   -407.7796124, CASCI Energy:   -407.8303791
d=4.3  RHF Energy:   -407.7758633, CASCI Energy:   -407.8302885
d=4.4  RHF Energy:   -407.7722923, CASCI Energy:   -407.8300614
d=4.5  RHF Energy:   -407.7688641, CASCI Energy:    -407.829711

Let's plot and compare HI-VQE results with HF and CASCI. You can observe that all HI-VQE calculations are well-matched with the classical reference result (CASCI).

fig, ax = plt.subplots(1, 1)
hf_energy = [v for key, v in rhf_result.items()]
casci_energy = [v for key, v in casci_result.items()]
hivqe_energy = [v for key, v in hivqe_result.items()]
distance_ref = [float(key) for key, v in rhf_result.items()]
distance = [float(key) for key, v in hivqe_result.items()]

ax.plot(distance_ref, hf_energy, "-o", label="RHF", c="blue")
ax.plot(distance_ref, casci_energy, "-o", label="CASCI", c="green")
ax.plot(distance, hivqe_energy, "x", label="HiVQE", c="red", markersize=20)
ax.legend(fontsize=20)
ax.tick_params("both", labelsize=16)
ax.set_xlabel("Bond distance (angstrom)", size=20)
ax.set_ylabel("Energy (Ha)", size=20)
ax.set_title("Li2S PES curve", size=20)
fig.set_size_inches(14, 8)

Output:

Output of the previous code cell

Part 2: FeP-NO (44Q)

The settings shown in this example need 44 qubits and run with max_states=400000000, more than M allows, so the calculator gives L.

Step 1: Map classical inputs to a quantum problem

Define the options for HI-VQE calculations

molecule_options_fepno = {
    "basis": "631g*",
    "active_orbitals": list(range(90, 112, 1)),
    "frozen_orbitals": list(range(0, 90, 1)),
    "charge": -1,
}

hivqe_options_fepno = {
    "shots": 2000,
    "max_iter": 40,
    "ansatz": "epa",
    "ansatz_entanglement": "linear",
    "ansatz_reps": 2,
    "amplitude_screening_tolerance": 1e-6,
}

Define FeP-NO geometries in dictionary format for different bond distances of Fe-N to calculate PES curve.

geometry_1_75 = """
Fe     9.910596    31.534095     1.798088
N     10.557481    31.888419    -0.055204
N     11.823496    31.255002     2.384659
N      9.292831    30.783362     3.568730
N      8.036805    31.418327     1.124265
C      9.784765    32.177349    -1.158798
C     10.612656    32.501029    -2.296868
C     11.903375    32.404043    -1.876832
C     11.859093    32.028943    -0.483750
C     12.965737    31.464698     1.641427
C     14.146517    31.236323     2.440231
C     13.713061    30.885870     3.681911
C     12.268752    30.896411     3.634891
C     10.067717    30.486167     4.664747
C      9.246224    30.053411     5.772052
C      7.957075    30.082846     5.336488
C      7.995710    30.538421     3.967046
C      6.900258    31.104497     1.836595
C      5.722470    31.251707     1.015333
C      6.148430    31.668586    -0.207993
C      7.587039    31.767438    -0.130483
C      8.399453    32.134197    -1.192329
H      7.912872    32.388031    -2.131079
C     12.984883    31.836053     0.306093
H     13.955948    31.977044    -0.162626
C     11.453768    30.560663     4.708020
H     11.940677    30.298823     5.644352
C      6.877071    30.697580     3.164102
H      5.907240    30.476797     3.603674
H     12.813946    32.569160    -2.441577
H     10.236332    32.758110    -3.280309
H     15.164312    31.335191     2.080201
H     14.299625    30.629109     4.556760
H      9.626524    29.758225     6.743433
H      7.053076    29.823583     5.875809
H      4.709768    31.058315     1.350561
H      5.561898    31.886355    -1.093106
N      9.832739    33.209042     2.298783
O      9.346337    34.075996     1.606023
"""

geometry_2_00 = """
Fe     9.917990    31.445558     1.778346
N     10.556809    31.866188    -0.055498
N     11.814089    31.227003     2.372666
N      9.297875    30.758246     3.550104
N      8.043584    31.397768     1.120485
C      9.784831    32.164652    -1.160219
C     10.611624    32.501801    -2.293514
C     11.902858    32.406547    -1.875160
C     11.859552    32.017818    -0.486307
C     12.960503    31.454432     1.636717
C     14.140770    31.242960     2.439615
C     13.708543    30.884151     3.678983
C     12.266351    30.874173     3.627468
C     10.070264    30.465070     4.655102
C      9.247247    30.053101     5.766681
C      7.958085    30.091201     5.332866
C      7.998432    30.529979     3.958727
C      6.901428    31.093932     1.833807
C      5.723289    31.255057     1.016540
C      6.151314    31.670649    -0.206350
C      7.589736    31.755538    -0.133074
C      8.400230    32.124963    -1.194447
H      7.913264    32.386655    -2.130914
C     12.983905    31.827747     0.302415
H     13.955696    31.979687    -0.161365
C     11.454251    30.533644     4.698234
H     11.941002    30.276716     5.636156
C      6.877444    30.689985     3.159940
H      5.907605    30.480118     3.604825
H     12.813105    32.581608    -2.437367
H     10.233725    32.768337    -3.273979
H     15.157796    31.357524     2.082132
H     14.295001    30.638320     4.557047
H      9.626721    29.768762     6.741623
H      7.051752    29.847502     5.875478
H      4.709710    31.071712     1.354640
H      5.565103    31.898376    -1.089333
N      9.840508    33.353531     2.373019
O      9.344561    34.158205     1.637232
"""

geometry_5_00 = """
Fe     9.918629    31.289202     1.717339
N     10.542914    31.832173    -0.080685
N     11.795572    31.199413     2.341831
N      9.294593    30.741247     3.513929
N      8.042689    31.359481     1.087282
C      9.775254    32.111817    -1.200449
C     10.600219    32.479101    -2.319680
C     11.891090    32.425876    -1.887580
C     11.847694    32.024341    -0.507342
C     12.945734    31.464689     1.611366
C     14.116395    31.289997     2.423572
C     13.685777    30.915122     3.663719
C     12.252381    30.861042     3.608186
C     10.062170    30.463021     4.634102
C      9.236749    30.104333     5.755782
C      7.945687    30.161198     5.324720
C      7.989641    30.552269     3.941498
C      6.892881    31.087489     1.815829
C      5.722676    31.253502     1.001149
C      6.153153    31.631057    -0.238233
C      7.586010    31.695401    -0.179773
C      8.390724    32.047572    -1.247553
H      7.903308    32.291586    -2.187969
C     12.973334    31.849872     0.283741
H     13.944682    32.031190    -0.169145
C     11.447158    30.518591     4.678739
H     11.934423    30.277429     5.619969
C      6.864795    30.711643     3.146118
H      5.893357    30.532078     3.599511
H     12.800139    32.636412    -2.439296
H     10.224017    32.743662    -3.301293
H     15.131785    31.441247     2.076257
H     14.273933    30.694315     4.546802
H      9.612512    29.848040     6.739754
H      7.036117    29.960530     5.879248
H      4.707408    31.099933     1.347803
H      5.564992    31.851940    -1.121294
N      9.666041    36.091609     3.085945
O      9.598728    37.226756     3.411299
"""

fepno_geometries = {
    "1.75": geometry_1_75,
    "2.00": geometry_2_00,
    "5.00": geometry_5_00,
}


hivqe_result_fepno = {}

Step 2 and 3: Optimize problem for quantum hardware execution and execute using the HI-VQE Chemistry function

Based on the setup of HI-VQE and geometries, obtain results sequentially.

Calculate the size once; the three geometries share their active space and max_states. The energies of the three runs are collected in hivqe_result_fepno.

size_fepno = calculate_function_size(
    fepno_geometries["1.75"],
    max_states=400000000,
    molecule_options=molecule_options_fepno,
)
print(size_fepno)  # "L"

hivqe_result_fepno = {}

Submit d(Fe-N) = 1.75 A˚\AA calculation.

hivqe_run_1_75 = hivqe.run(
    geometry=fepno_geometries["1.75"],
    backend_name=backend_name,
    function_size=size_fepno,
    max_states=400000000,
    max_expansion_states=100,
    molecule_options=molecule_options_fepno,
    hivqe_options=hivqe_options_fepno,
)
info_jobid_1_75 = hivqe_run_1_75.job_id

Track the job and retrieve the result for d(Fe-N) = 1.75 A˚\AA calculation.

submitted_job_1_75 = catalog.get_job_by_id(info_jobid_1_75)
stat = submitted_job_1_75.status()
print(submitted_job_1_75.job_id, stat)
if stat == "DONE":
    hivqe_run_1_75_energy = submitted_job_1_75.result()["energy"]
    print(f"Completed HI-VQE calculation, Energy {hivqe_run_1_75_energy}")
    hivqe_result_fepno["1.75"] = hivqe_run_1_75_energy

Submit d(Fe-N) = 2.00 A˚\AA calculation.

hivqe_run_2_00 = hivqe.run(
    geometry=fepno_geometries["2.00"],
    backend_name=backend_name,
    function_size=size_fepno,
    max_states=400000000,
    max_expansion_states=100,
    molecule_options=molecule_options_fepno,
    hivqe_options=hivqe_options_fepno,
)
info_jobid_2_00 = hivqe_run_2_00.job_id

Track the job and retrieve the result for d(Fe-N) = 2.00 A˚\AA calculation.

submitted_job_2_00 = catalog.get_job_by_id(info_jobid_2_00)
stat = submitted_job_2_00.status()
print(submitted_job_2_00.job_id, stat)
if stat == "DONE":
    hivqe_run_2_00_energy = submitted_job_2_00.result()["energy"]
    print(f"Completed HI-VQE calculation, Energy {hivqe_run_2_00_energy}")
    hivqe_result_fepno["2.00"] = hivqe_run_2_00_energy

Submit d(Fe-N) = 5.00 A˚\AA calculation.

hivqe_run_5_00 = hivqe.run(
    geometry=fepno_geometries["5.00"],
    backend_name=backend_name,
    function_size=size_fepno,
    max_states=400000000,
    max_expansion_states=100,
    molecule_options=molecule_options_fepno,
    hivqe_options=hivqe_options_fepno,
)
info_jobid_5_00 = hivqe_run_5_00.job_id

Track the job and retrieve the result for d(Fe-N) = 5.00 A˚\AA calculation.

submitted_job_5_00 = catalog.get_job_by_id(info_jobid_5_00)
stat = submitted_job_5_00.status()
print(submitted_job_5_00.job_id, stat)
if stat == "DONE":
    hivqe_run_5_00_energy = submitted_job_5_00.result()["energy"]
    print(f"Completed HI-VQE calculation, Energy {hivqe_run_5_00_energy}")
    hivqe_result_fepno["5.00"] = hivqe_run_5_00_energy

These are the energies from the three runs, so that the comparison below works without waiting for your own jobs. Skip this cell to use your own.

hivqe_result_fepno = {
    "1.75": -2373.681781,
    "2.00": -2373.694128,
    "5.00": -2373.637807,
}

Step 4: Post-process and compare with classical methods

Classical reference calculation (CASCI-DMRG, maxM=800) results are provided for (22o,22e) to validate HI-VQE results.

rhf_result_fepno = {
    "1.75": -2373.59331683504,
    "2.00": -2373.60640773065,
    "5.00": -2373.50214278007,
}
casci_result_fepno = {
    "1.75": -2373.6827,
    "2.00": -2373.6948,
    "5.00": -2373.6393,
}
fig, ax = plt.subplots(1, 1)
hf_energy = [v for key, v in rhf_result_fepno.items()]
casci_energy = [v for key, v in casci_result_fepno.items()]
hivqe_energy = [v for key, v in hivqe_result_fepno.items()]
distance_ref = [float(key) for key, v in rhf_result_fepno.items()]
distance = [float(key) for key, v in hivqe_result_fepno.items()]

ax.plot(distance_ref, hf_energy, "-o", label="RHF", c="blue")
ax.plot(distance_ref, casci_energy, "-o", label="CASCI", c="green")
ax.plot(distance, hivqe_energy, "x", label="HiVQE", c="red", markersize=20)
ax.legend(fontsize=20)
ax.tick_params("both", labelsize=16)
ax.set_xlabel(r"Fe-N bond distance ($\AA$)", size=20)
ax.set_ylabel("Energy (Ha)", size=20)
ax.set_title("FeP-NO PES curve", size=20)
fig.set_size_inches(14, 8)

Output:

Output of the previous code cell

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